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6r^2-18r-240=0
a = 6; b = -18; c = -240;
Δ = b2-4ac
Δ = -182-4·6·(-240)
Δ = 6084
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$r_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$r_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{6084}=78$$r_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-18)-78}{2*6}=\frac{-60}{12} =-5 $$r_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-18)+78}{2*6}=\frac{96}{12} =8 $
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